What is the line (0,20),(13500,4.5) ?

The line (0,20),(13500,4.5) is y=-0.00114…x+20

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line (0,20),(13500,4.5)

line

(0, 20), (13500, 4.5)

y = - 0.00114 \dots x + 20

Solution steps

Find the line

y = mx + b

passing through

(0, 20)

(13500, 4.5)

Compute the slope

(0, 20), (13500, 4.5) : m = - 0.00114 \dots

Compute the

y

intercept:

b = 20

Construct the line equation

y = mx + b

where

m = - 0.00114 \dots

and

b = 20

y = - 0.00114 \dots x + 20

y = \frac{( x - 4 )}{( x + 1 )}

x^{3} - x

f (x) = - (x)^{2}

f (x) = \frac{3}{2 x + 1}

\frac{3}{\frac{2}{2 + x} + 2}

What is the line (0,20),(13500,4.5) ?
The line (0,20),(13500,4.5) is y=-0.00114…x+20