What is the domain of f(x)= 2/(x^2-9) ?

The domain of f(x)= 2/(x^2-9) is x 3

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domain of f(x)= 2/(x^2-9)

domain

f (x) = \frac{2}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = x + 5

\frac{2 + x}{x ^{2} ( 1 - x )}

f (x) = \frac{e ^{1 - 2 x}}{x ^{2} - 9}

f (x) = x^{3} - 9 x^{2} + 15

f (x) = 2 x^{3} - 39 x^{2} + 240 x + 8

What is the domain of f(x)= 2/(x^2-9) ?
The domain of f(x)= 2/(x^2-9) is x<-3\lor-3<x<3\lor x>3