What is the domain of 1/(sqrt(x-1)) ?

The domain of 1/(sqrt(x-1)) is x>1

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domain of 1/(sqrt(x-1))

domain

\frac{1}{x - 1}

x > 1

Solution steps

Find non-negative values for radicals:

x \geq 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x > 1

f (x) = - x - 3

\frac{- 4 x + 4}{5 x - 1}

f (x) = 4 x^{3} - 6 x^{2} + 8 x - 3

f (x) = \frac{x + 5}{x ^{2} + 3 x + 2}

f (x) = \frac{( x ^{2} - 9 )}{x ^{2} + 2 x - 35}