What is the range of f(x)=2x^2+24x+76,-6<= x<= 2 ?

The range of f(x)=2x^2+24x+76,-6<= x<= 2 is 4<= f(x)<= 132

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range of f(x)=2x^2+24x+76,-6<= x<= 2

range

f (x) = 2 x^{2} + 24 x + 76, - 6 \leq x \leq 2

4 \leq f (x) \leq 132

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

2 x^{2} + 24 x + 76, - 6 \leq x \leq 2 : - 6 \leq x \leq 2

Extreme Points of

2 x^{2} + 24 x + 76, - 6 \leq x \leq 2 :

Minimum

(- 6, 4),

Maximum

(2, 132)

Find the range for the interval

- 6 \leq x \leq 2 : 4 \leq f (x) \leq 132

Combine the ranges of all domain intervals to obtain the function range

4 \leq f (x) \leq 132

- x - 2 - 3

f (x) = 2 x + 6

f (x) = \frac{8}{x} + \frac{10}{x + 10}

f (x) = \frac{1}{4}

f (x) = 2 x - 6

What is the range of f(x)=2x^2+24x+76,-6<= x<= 2 ?
The range of f(x)=2x^2+24x+76,-6<= x<= 2 is 4<= f(x)<= 132