What is the inverse of f(x)=7-2(x-1)^2 ?

The inverse of f(x)=7-2(x-1)^2 is sqrt(-(x-7)/2)+1,-sqrt(-(x-7)/2)+1

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inverse of f(x)=7-2(x-1)^2

inverse

f (x) = 7 - 2 (x - 1)^{2}

- \frac{x - 7}{2} + 1, - - \frac{x - 7}{2} + 1

Solution steps

y = 7 - 2 (x - 1)^{2}

Replace

x

with

y

x = 7 - 2 (y - 1)^{2}

Solve for

y, x = 7 - 2 (y - 1)^{2}

- \frac{x - 7}{2} + 1, - - \frac{x - 7}{2} + 1

y = \frac{x + 1}{x ^{2} - 4}

y = x + 5

g (x) = x^{2} - 9

f (x) = \frac{x - 2}{x ^{2} - 4}

f (x) = arctan (x)

What is the inverse of f(x)=7-2(x-1)^2 ?
The inverse of f(x)=7-2(x-1)^2 is sqrt(-(x-7)/2)+1,-sqrt(-(x-7)/2)+1