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Popular >

extreme f(x)=2x^2-8

Solution

extreme points

f (x) = 2 x^{2} - 8

Solution

Minimum (0, - 8)

Solution steps

f^{'} (x) = 4 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

2 x^{2} - 8 : - 8

Minimum (0, - 8)

Popular Examples

asymptotes of f(x)=(10-2x^2)/(x^2-4)asymptotes

f (x) = \frac{10 - 2 x ^{2}}{x ^{2} - 4}

critical 13x^3+13/2 x^2+36x+7 critical points

13 x^{3} + \frac{13}{2} x^{2} + 36 x + 7

inverse of f(x)=-(x+3)^2-4 inverse

f (x) = - (x + 3)^{2} - 4

intercepts of f(x)=-2(x-2)^2+5 intercepts

f (x) = - 2 (x - 2)^{2} + 5

intercepts of f(x)=2x^2-4x-1 intercepts

f (x) = 2 x^{2} - 4 x - 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-8 ?
The extreme f(x)=2x^2-8 is Minimum(0,-8)