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Popular Functions >

extreme f(x)=2x^2+6x+10

Solution

extreme

Solution

Minimum (- \frac{3}{2}, \frac{11}{2})

Solution steps

f^{'} (x) = 4 x + 6

Find intervals:

Decreasing

: - \infty < x < - \frac{3}{2},

Increasing

: - \frac{3}{2} < x < \infty

Plug

x = - \frac{3}{2}

into

2 x^{2} + 6 x + 10 : \frac{11}{2}

Minimum (- \frac{3}{2}, \frac{11}{2})

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2+6x+10 ?
The extreme f(x)=2x^2+6x+10 is Minimum(-3/2 , 11/2)