What is the domain of 1/(sqrt(x^2-4x-5)) ?

The domain of 1/(sqrt(x^2-4x-5)) is x 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of 1/(sqrt(x^2-4x-5))

domain

\frac{1}{x ^{2} - 4 x - 5}

x < - 1 or x > 5

Interval Notation

(- \infty, - 1) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 5

Find undefined (singularity) points:

x = 5, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 5

f (x) = - \frac{8}{x}

f (x) = 3 x^{2} + \frac{4}{x ^{2}}

f (x) = \frac{4 - x}{4}

\frac{x ^{4}}{2} - \frac{3 x ^{2}}{2}

x^{2} - 4 x + 1

What is the domain of 1/(sqrt(x^2-4x-5)) ?
The domain of 1/(sqrt(x^2-4x-5)) is x<-1\lor x>5