What is the extreme f(x)=2x^3-24x-6 ?

The extreme f(x)=2x^3-24x-6 is Maximum(-2,26),Minimum(2,-38)

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extreme f(x)=2x^3-24x-6

extreme points

f (x) = 2 x^{3} - 24 x - 6

Maximum (- 2, 26), Minimum (2, - 38)

Solution steps

f^{'} (x) = 6 x^{2} - 24

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

2 x^{3} - 24 x - 6 : 26

Maximum (- 2, 26)

Plug

x = 2

into

2 x^{3} - 24 x - 6 : - 38

Minimum (2, - 38)

Maximum (- 2, 26), Minimum (2, - 38)

f (t) = t^{4} - \frac{2}{3} t^{6}

f (x) = 7 sin (x)

\frac{x ^{3} - x}{x ^{2} - 4}

f (x) = 3 + 1

y = x^{2} - x - 20

What is the extreme f(x)=2x^3-24x-6 ?
The extreme f(x)=2x^3-24x-6 is Maximum(-2,26),Minimum(2,-38)