What is the inflection cos(2x+5) ?

The inflection cos(2x+5) is ((-10+5pi)/4+pin,0),((-10+7pi)/4+pin,0)

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inflection cos(2x+5)

inflection points

cos (2 x + 5)

(\frac{- 10 + 5 π}{4} + πn, 0), (\frac{- 10 + 7 π}{4} + πn, 0)

Solution steps

Find where

f^{''} (x)

is equal to zero or undefined

x = \frac{- 10 + 5 π}{4} + πn, x = \frac{- 10 + 7 π}{4} + πn

Identify inflection points not in domain or where

f (x)

is not continuous

Domain of

cos (2 x + 5) : - \infty < x < \infty

All inflection points are in domain and not on domain edges

x = \frac{- 10 + 5 π}{4} + πn, x = \frac{- 10 + 7 π}{4} + πn

Find intervals:

Concave Downward

: πn \leq x < \frac{- 10 + 5 π}{4} + πn,

Concave Upward

: \frac{- 10 + 5 π}{4} + πn < x < \frac{- 10 + 7 π}{4} + πn,

Concave Downward

: \frac{- 10 + 7 π}{4} + πn < x < π + πn

Plug

x = \frac{- 10 + 5 π}{4} + πn

into

cos (2 x + 5) : 0

(\frac{- 10 + 5 π}{4} + πn, 0)

Plug

x = \frac{- 10 + 7 π}{4} + πn

into

cos (2 x + 5) : 0

(\frac{- 10 + 7 π}{4} + πn, 0)

(\frac{- 10 + 5 π}{4} + πn, 0), (\frac{- 10 + 7 π}{4} + πn, 0)

f (x) = \frac{3 x}{x - 1}

5 cos (2 x + \frac{π}{2})

f (x) = \frac{x + 2}{x + 9}

(10.3) (30.1)

f (x) = (x - 8)^{2}

What is the inflection cos(2x+5) ?
The inflection cos(2x+5) is ((-10+5pi)/4+pin,0),((-10+7pi)/4+pin,0)