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Popular >

extreme f(x)=-4-x+x^2

Solution

extreme points

f (x) = - 4 - x + x^{2}

Solution

Minimum (\frac{1}{2}, - \frac{17}{4})

Solution steps

f^{'} (x) = 2 x - 1

Find intervals:

Decreasing

: - \infty < x < \frac{1}{2},

Increasing

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

- 4 - x + x^{2} : - \frac{17}{4}

Minimum (\frac{1}{2}, - \frac{17}{4})

Popular Examples

extreme f(x)=x^2(4-4x)^2 extreme points

f (x) = x^{2} (4 - 4 x)^{2}

extreme f(x)=3x^2-24x+9,0<= x<= 9 extreme points

f (x) = 3 x^{2} - 24 x + 9, 0 \leq x \leq 9

extreme f(x)=2x^3-9x^2+12x extreme points

f (x) = 2 x^{3} - 9 x^{2} + 12 x

domain of f(x)=2-cos(3x)domain

f (x) = 2 - cos (3 x)

slope ofintercept 4x+3y=21 slope intercept

4 x + 3 y = 21

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-4-x+x^2 ?
The extreme f(x)=-4-x+x^2 is Minimum(1/2 ,-17/4)