What is the inverse of f(x)=-8x^2-3 ?

The inverse of f(x)=-8x^2-3 is sqrt(-(x+3)/8),-sqrt(-(x+3)/8)

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inverse of f(x)=-8x^2-3

inverse

f (x) = - 8 x^{2} - 3

- \frac{x + 3}{8}, - - \frac{x + 3}{8}

Solution steps

y = - 8 x^{2} - 3

Replace

x

with

y

x = - 8 y^{2} - 3

Solve for

y, x = - 8 y^{2} - 3

- \frac{x + 3}{8}, - - \frac{x + 3}{8}

\frac{2 + x}{4 - x}

f (x) = \frac{x + 1}{x ^{2} - 4}

(- 4.5) (0.9)

f (x) = - 3 - x - 2

f (x) = \frac{x ^{2} + 3 x}{x ^{2} + x - 6}

What is the inverse of f(x)=-8x^2-3 ?
The inverse of f(x)=-8x^2-3 is sqrt(-(x+3)/8),-sqrt(-(x+3)/8)