What is the critical f(x,)=-3/2 x^4+6x ?

The critical f(x,)=-3/2 x^4+6x is x=1

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critical f(x,)=-3/2 x^4+6x

critical points

f (x,) = - \frac{3}{2} x^{4} + 6 x

x = 1

Solution steps

- \frac{3}{2} x^{4} + 6 x

Find where

f^{'} (x)

is equal to zero or undefined

x = 1

Identify critical points not in

f (x)

domain

Domain of

- \frac{3}{2} x^{4} + 6 x : - \infty < x < \infty

All critical points are in domain

x = 1

5 x - 6 y = 42

2^{\frac{x}{3}} + 4

32 y = - 22 x + 10

f (x) = x^{4} - 7 x^{2} - 6 x

(1, - 2), (5, - 6)