What is the inverse of f(x)=(9-3x)^{7/2} ?

The inverse of f(x)=(9-3x)^{7/2} is -(x^{2/7}-9)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(9-3x)^{7/2}

inverse

f (x) = (9 - 3 x)^{\frac{7}{2}}

- \frac{x ^{\frac{2}{7}} - 9}{3}

Solution steps

y = (9 - 3 x)^{\frac{7}{2}}

Replace

x

with

y

x = (9 - 3 y)^{\frac{7}{2}}

Solve for

y, x = (9 - 3 y)^{\frac{7}{2}}

- \frac{x ^{\frac{2}{7}} - 9}{3}

f (x) = \frac{9}{( x - 3 ) ^{3}}

f (x) = - (x)

x + 5 y = - 15

f (x) = 2 - x + 4

f (x) = \frac{4}{x ^{2}}

What is the inverse of f(x)=(9-3x)^{7/2} ?
The inverse of f(x)=(9-3x)^{7/2} is -(x^{2/7}-9)/3