What is the domain of f(x)=sqrt(x^2-4x+3) ?

The domain of f(x)=sqrt(x^2-4x+3) is x = 3

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domain of f(x)=sqrt(x^2-4x+3)

domain

f (x) = x^{2} - 4 x + 3

x \leq 1 or x \geq 3

Solution steps

Find non-negative values for radicals:

x \leq 1 or x \geq 3

The function domain

x \leq 1 or x \geq 3

\frac{1}{x - 4}

f (x) = (x - 4)^{2} + 2, x \geq 4

f (x) = \frac{x ^{2} + 1}{x + 1}

6 x^{3} + 45 x^{2} - 108 x + 6

f (x) = \frac{3 x}{x ^{2} - 4}

What is the domain of f(x)=sqrt(x^2-4x+3) ?
The domain of f(x)=sqrt(x^2-4x+3) is x<= 1\lor x>= 3