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range of f(x)=(x^3+x^2+x+1)/(|x+1|)inverse of f(x)= x/(1-x)inverse of x^2-7,x>= 0asymptotes of f(x)=(2x^2-9)/(x^2-9)domain of sqrt(9+x^2)
Frequently Asked Questions (FAQ)
What is the midpoint (8,3),(9.5,-3) ?
The midpoint (8,3),(9.5,-3) is (8.75,0)