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Popular Functions >

extreme f(x)=2x^2-6x+8

Solution

extreme

Solution

Minimum (\frac{3}{2}, \frac{7}{2})

Solution steps

f^{'} (x) = 4 x - 6

Find intervals:

Decreasing

: - \infty < x < \frac{3}{2},

Increasing

: \frac{3}{2} < x < \infty

Plug

x = \frac{3}{2}

into

2 x^{2} - 6 x + 8 : \frac{7}{2}

Minimum (\frac{3}{2}, \frac{7}{2})

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-6x+8 ?
The extreme f(x)=2x^2-6x+8 is Minimum(3/2 , 7/2)