What is the inverse of f(x)=sqrt(-4x^2+12) ?

The inverse of f(x)=sqrt(-4x^2+12) is sqrt(-(x^2-12)/4),-sqrt(-(x^2-12)/4)

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inverse of f(x)=sqrt(-4x^2+12)

inverse

f (x) = - 4 x^{2} + 12

- \frac{x ^{2} - 12}{4}, - - \frac{x ^{2} - 12}{4}

Solution steps

y = - 4 x^{2} + 12

Replace

x

with

y

x = - 4 y^{2} + 12

Solve for

y, x = - 4 y^{2} + 12

- \frac{x ^{2} - 12}{4}, - - \frac{x ^{2} - 12}{4}

5 t + 6

- \frac{1}{2} x^{2} + 2 x + 3

f (x) = x^{2} - 2 x + 3

f (x) = \frac{9 x + 4}{x - 1}

What is the inverse of f(x)=sqrt(-4x^2+12) ?
The inverse of f(x)=sqrt(-4x^2+12) is sqrt(-(x^2-12)/4),-sqrt(-(x^2-12)/4)