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Popular Functions >

range of g(x)=-(x+5)^2+2

Solution

range

Solution

f (x) \leq 2

+1

Interval Notation

Solution steps

Vertex of

- (x + 5)^{2} + 2 :

Maximum

(- 5, 2)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (- 5, 2)

f (x) \leq 2

Graph

Popular Examples

inverse of y= 1/(x+2)

extreme f(x)=2x^3-3x^2-12x+4

inverse of f(x)=(2x-3)^2+1

midpoint (3,6),(5.5,5)

inflection y=(x^3)/3-2x^2-12x

Frequently Asked Questions (FAQ)

What is the range of g(x)=-(x+5)^2+2 ?
The range of g(x)=-(x+5)^2+2 is f(x)<= 2