What is the critical f(x)=(x^3)/3-9x ?

The critical f(x)=(x^3)/3-9x is x=-3,x=3

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critical f(x)=(x^3)/3-9x

critical points

f (x) = \frac{x ^{3}}{3} - 9 x

x = - 3, x = 3

Solution steps

\frac{x ^{3}}{3} - 9 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{3}}{3} - 9 x : - \infty < x < \infty

All critical points are in domain

x = - 3, x = 3

f (x) = x^{2} - 4 x

\frac{3 x + 6}{x ^{2} - x - 2}

f (x) = 4 x - 10

f (x) = - 5 (- x - 6)