What is the critical 0.5x-(2560)/(x^2) ?

The critical 0.5x-(2560)/(x^2) is x=-8\sqrt[3]{20}

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critical 0.5x-(2560)/(x^2)

critical

x = - 8320

Solution steps

0.5 x - \frac{2560}{x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 8320, x = 0

Identify critical points not in

f (x)

domain

Domain of

0.5 x - \frac{2560}{x ^{2}} : x < 0 or x > 0

0.5 x - \frac{2560}{x ^{2}}

is not defined at

x = 0

, therefore:

x = - 8320

What is the critical 0.5x-(2560)/(x^2) ?
The critical 0.5x-(2560)/(x^2) is x=-8\sqrt[3]{20}