What is the critical 0.0135x^2-1.096x+41.3 ?

The critical 0.0135x^2-1.096x+41.3 is x= 1096/27

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critical 0.0135x^2-1.096x+41.3

critical points

0.0135 x^{2} - 1.096 x + 41.3

x = \frac{1096}{27}

Solution steps

0.0135 x^{2} - 1.096 x + 41.3

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1096}{27}

Identify critical points not in

f (x)

domain

Domain of

0.0135 x^{2} - 1.096 x + 41.3 : - \infty < x < \infty

All critical points are in domain

x = \frac{1096}{27}

f (x) = 4 x^{3} e^{x}

s^{3}

f (x) = \frac{x - 4}{5}

(- 3, 1), (1, - 3)

f (x) = \frac{1}{x ^{2} + 1}

What is the critical 0.0135x^2-1.096x+41.3 ?
The critical 0.0135x^2-1.096x+41.3 is x= 1096/27