What is the inverse of f(x)=(3-2x)^2-1 ?

The inverse of f(x)=(3-2x)^2-1 is -(sqrt(x+1)-3)/2 ,-(-sqrt(x+1)-3)/2

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inverse of f(x)=(3-2x)^2-1

inverse

f (x) = (3 - 2 x)^{2} - 1

- \frac{x + 1 - 3}{2}, - \frac{- x + 1 - 3}{2}

Solution steps

y = (3 - 2 x)^{2} - 1

Replace

x

with

y

x = (3 - 2 y)^{2} - 1

Solve for

y, x = (3 - 2 y)^{2} - 1

- \frac{x + 1 - 3}{2}, - \frac{- x + 1 - 3}{2}

ln (x - 5)

x^{2} y^{2} + x y = 1

tan (3 x)

f (x) = 4 x + 4

f (x) = 15 - x^{2}, x \geq 0

What is the inverse of f(x)=(3-2x)^2-1 ?
The inverse of f(x)=(3-2x)^2-1 is -(sqrt(x+1)-3)/2 ,-(-sqrt(x+1)-3)/2