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Popular >

extreme f(x)=2x^2-2x+1

Solution

extreme points

f (x) = 2 x^{2} - 2 x + 1

Solution

Minimum (\frac{1}{2}, \frac{1}{2})

Solution steps

f^{'} (x) = 4 x - 2

Find intervals:

Decreasing

: - \infty < x < \frac{1}{2},

Increasing

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

2 x^{2} - 2 x + 1 : \frac{1}{2}

Minimum (\frac{1}{2}, \frac{1}{2})

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g (x) = - \frac{1}{3} x + 1

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-2x+1 ?
The extreme f(x)=2x^2-2x+1 is Minimum(1/2 , 1/2)