What is the perpendicular 5y=2x-4,(0,7) ?

The perpendicular 5y=2x-4,(0,7) is y=-5/2 x+7

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perpendicular 5y=2x-4,(0,7)

perpendicular

5 y = 2 x - 4, (0, 7)

y = - \frac{5}{2} x + 7

Solution steps

Find the line

y = mx + b

perpendicular to

5 y = 2 x - 4

that passes through

(0, 7)

Find the slope of

5 y = 2 x - 4 : m = \frac{2}{5}

Compute the slope of the perpendicular line:

m_{p} = - \frac{5}{2}

Find the line with slope m=

- \frac{5}{2}

and passing through

(0, 7) : y = - \frac{5}{2} x + 7

y = - \frac{5}{2} x + 7

\frac{- x + 3}{x ^{2} - 1}

x^{2} - x - 6

(- 2, - 4), (4, 4)

6 x - 3 y = 9

f (x) = 5 x - 3

What is the perpendicular 5y=2x-4,(0,7) ?
The perpendicular 5y=2x-4,(0,7) is y=-5/2 x+7