What is the perpendicular 5x-10y=1,(1/2 ,-2/7) ?

The perpendicular 5x-10y=1,(1/2 ,-2/7) is y=-2x+5/7

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perpendicular 5x-10y=1,(1/2 ,-2/7)

perpendicular

5 x - 10 y = 1, (\frac{1}{2}, - \frac{2}{7})

y = - 2 x + \frac{5}{7}

Solution steps

Find the line

y = mx + b

perpendicular to

5 x - 10 y = 1

that passes through

(\frac{1}{2}, - \frac{2}{7})

Find the slope of

5 x - 10 y = 1 : m = \frac{1}{2}

Compute the slope of the perpendicular line:

m_{p} = - 2

Find the line with slope m=

- 2

and passing through

(\frac{1}{2}, - \frac{2}{7}) : y = - 2 x + \frac{5}{7}

y = - 2 x + \frac{5}{7}

f (x) = \frac{1}{8 - x}

x^{2} - 5 x + 6

\frac{x ^{2} - 16}{x ^{3} - 5 x ^{2} + 4 x}

f (x) = x^{2} 4 - x

\frac{x + 7}{x}

What is the perpendicular 5x-10y=1,(1/2 ,-2/7) ?
The perpendicular 5x-10y=1,(1/2 ,-2/7) is y=-2x+5/7