What is the critical 2x^3-7x^2+2x+3 ?

The critical 2x^3-7x^2+2x+3 is x=(7-sqrt(37))/6 ,x=(7+sqrt(37))/6

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critical 2x^3-7x^2+2x+3

critical points

2 x^{3} - 7 x^{2} + 2 x + 3

x = \frac{7 - 37}{6}, x = \frac{7 + 37}{6}

Solution steps

2 x^{3} - 7 x^{2} + 2 x + 3

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{7 - 37}{6}, x = \frac{7 + 37}{6}

Identify critical points not in

f (x)

domain

Domain of

2 x^{3} - 7 x^{2} + 2 x + 3 : - \infty < x < \infty

All critical points are in domain

x = \frac{7 - 37}{6}, x = \frac{7 + 37}{6}

f (x) = 2 x - 4 + 8

x^{2} + 2 x - 8

f (x) = 2 x^{7} - 9

y = 6 x - 5

\frac{( \frac{x}{2 x ^{2} - 5} )}{x}

What is the critical 2x^3-7x^2+2x+3 ?
The critical 2x^3-7x^2+2x+3 is x=(7-sqrt(37))/6 ,x=(7+sqrt(37))/6