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Popular >

range of 4x^2+7

Solution

range

4 x^{2} + 7

Solution

f (x) \geq 7

+1

Solution steps

Vertex of

4 x^{2} + 7 :

Minimum

(0, 7)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 4,

Vertex

(x_{v}, y_{v}) = (0, 7)

f (x) \geq 7

Popular Examples

inverse of (5+x)/(4-2x)inverse

\frac{5 + x}{4 - 2 x}

domain of f(x)=sqrt(1/(\sqrt{x))}domain

f (x) = \frac{1}{x}

extreme f(x)=(ln(x))/x extreme points

f (x) = \frac{ln ( x )}{x}

inverse of f(x)=((x+3))/(x-4)inverse

f (x) = \frac{( x + 3 )}{x - 4}

domain of f(x)=sin(2x)domain

f (x) = sin (2 x)

Frequently Asked Questions (FAQ)

What is the range of 4x^2+7 ?
The range of 4x^2+7 is f(x)>= 7