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midpoint (-5,-2),(2,3)slope ofintercept-5x+4y-53=0asymptotes of f(x)=(x^2+36)/(x^2-36)range of sqrt((4x)/(x^2+1))inverse of f(x)=(x-1)/4
Frequently Asked Questions (FAQ)
What is the inverse of f(x)=(3-x)^2 ?
The inverse of f(x)=(3-x)^2 is -sqrt(x)+3,sqrt(x)+3