What is the critical f(x)=x^{7/2}-8x^2 ?

The critical f(x)=x^{7/2}-8x^2 is x=0,x=(8*2^{1/3})/(49^{1/3)}

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critical f(x)=x^{7/2}-8x^2

critical points

f (x) = x^{\frac{7}{2}} - 8 x^{2}

x = 0, x = \frac{8 \cdot 2 ^{\frac{1}{3}}}{4 9 ^{\frac{1}{3}}}

Solution steps

x^{\frac{7}{2}} - 8 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = \frac{8 \cdot 2 ^{\frac{1}{3}}}{4 9 ^{\frac{1}{3}}}

Identify critical points not in

f (x)

domain

Domain of

x^{\frac{7}{2}} - 8 x^{2} : x \geq 0

All critical points are in domain

x = 0, x = \frac{8 \cdot 2 ^{\frac{1}{3}}}{4 9 ^{\frac{1}{3}}}

f (x) = 6 x

(26.7, - 6.3), (32.7, - 14.3)

f (x) = - 2 x + 3

f (x) = \frac{5}{x - 3}

arctan (tan (θ))

What is the critical f(x)=x^{7/2}-8x^2 ?
The critical f(x)=x^{7/2}-8x^2 is x=0,x=(8*2^{1/3})/(49^{1/3)}