What is the extreme f(x)=4sqrt(x)-2x ?

The extreme f(x)=4sqrt(x)-2x is Maximum(0,0),Minimum(1,2)

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extreme f(x)=4sqrt(x)-2x

extreme points

f (x) = 4 x - 2 x

Maximum (0, 0), Minimum (1, 2)

Solution steps

f^{'} (x) = \frac{2}{x} - 2

Find intervals:

Decreasing

: 0 \leq x < 1,

Increasing

: 1 < x < \infty

Plug

x = 0

into

4 x - 2 x : 0

Maximum (0, 0)

Plug

x = 1

into

4 x - 2 x : 2

Minimum (1, 2)

Maximum (0, 0), Minimum (1, 2)

f (x) = \frac{2}{x ^{2} - 2 x - 3}

f (x) = \frac{2 + x}{1 - 2 x}

\frac{6 x}{x - 2}

y = - \frac{9}{2 x ^{\frac{3}{2}}}

f (x) = x

What is the extreme f(x)=4sqrt(x)-2x ?
The extreme f(x)=4sqrt(x)-2x is Maximum(0,0),Minimum(1,2)