What is the range of f(x)=((1-x))/(2x-1) ?

The range of f(x)=((1-x))/(2x-1) is f(x) -1/2

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range of f(x)=((1-x))/(2x-1)

range

f (x) = \frac{( 1 - x )}{2 x - 1}

f (x) < - \frac{1}{2} or f (x) > - \frac{1}{2}

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{1 - x}{2 x - 1}

Inverse of

\frac{1 - x}{2 x - 1} : \frac{1 + x}{2 x + 1}

\frac{1 + x}{2 x + 1}

Find the domain of each inverse function

Domain of

\frac{1 + x}{2 x + 1} : x < - \frac{1}{2} or x > - \frac{1}{2}

Combine the intervals

f (x) < - \frac{1}{2} or f (x) > - \frac{1}{2}

y = 3^{2 x - 4}

f (x) = x^{3} - x^{2} - 6 x

(x^{2} - 2)^{3}

y = - \frac{3}{4} x - 2

f (x) = - \frac{5}{4} x

What is the range of f(x)=((1-x))/(2x-1) ?
The range of f(x)=((1-x))/(2x-1) is f(x)<-1/2 \lor f(x)>-1/2