What is the critical x^4-3x^2-4 ?

The critical x^4-3x^2-4 is x=-sqrt(3/2),x=0,x=sqrt(3/2)

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critical x^4-3x^2-4

critical points

x^{4} - 3 x^{2} - 4

x = - \frac{3}{2}, x = 0, x = \frac{3}{2}

Solution steps

x^{4} - 3 x^{2} - 4

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{3}{2}, x = 0, x = \frac{3}{2}

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 3 x^{2} - 4 : - \infty < x < \infty

All critical points are in domain

x = - \frac{3}{2}, x = 0, x = \frac{3}{2}

\frac{x ^{2}}{x ^{2} - 1}

f (x) = x^{4} + 10 x^{3} + 30 x^{2} + 25 x

2 x^{2} - 4 x

x^{4} - 4 x^{3}

f (x) = - (x + 2)^{2} + 3

What is the critical x^4-3x^2-4 ?
The critical x^4-3x^2-4 is x=-sqrt(3/2),x=0,x=sqrt(3/2)