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Popular >

distance (2,5),(-2,-3)

Solution

distance

(2, 5), (- 2, - 3)

Solution

45

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(2, 5)

and

(- 2, - 3)

is

= (- 2 - 2)^{2} + (- 3 - 5)^{2}

Simplify

= 45

Popular Examples

inverse of f(x)= 1/2 x+3 inverse

f (x) = \frac{1}{2} x + 3

inverse of f(x)=2-3e^{x-4}inverse

f (x) = 2 - 3 e^{x - 4}

critical y=e^{-x^2}critical points

y = e^{- x^{2}}

extreme f(x)=x^2+2x+6 extreme points

f (x) = x^{2} + 2 x + 6

symmetry-2(x+3)^2+1 symmetry

- 2 (x + 3)^{2} + 1

Frequently Asked Questions (FAQ)

What is the distance (2,5),(-2,-3) ?
The distance (2,5),(-2,-3) is 4sqrt(5)