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Popular >

midpoint (0,8),(4,-6)

Solution

midpoint

(0, 8), (4, - 6)

Solution

(2, 1)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (0, 8), (x_{2}, y_{2}) = (4, - 6)

= (\frac{4 + 0}{2}, \frac{- 6 + 8}{2})

Refine

= (2, 1)

Popular Examples

domain of f(x)=e^{-2t}domain

f (x) = e^{- 2 t}

inverse of f(x)=-2x^2+5x-6 inverse

f (x) = - 2 x^{2} + 5 x - 6

midpoint (6,4),(4, 5/3)midpoint

(6, 4), (4, \frac{5}{3})

inverse of f(x)=(x-3)^2+2 inverse

f (x) = (x - 3)^{2} + 2

midpoint (2,-4),(8,4)midpoint

(2, - 4), (8, 4)

Frequently Asked Questions (FAQ)

What is the midpoint (0,8),(4,-6) ?
The midpoint (0,8),(4,-6) is (2,1)