What is the extreme y=x^3-5x^2-8x+6 ?

The extreme y=x^3-5x^2-8x+6 is Maximum(-2/3 , 238/27),Minimum(4,-42)

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extreme y=x^3-5x^2-8x+6

extreme

Maximum (- \frac{2}{3}, \frac{238}{27}), Minimum (4, - 42)

Solution steps

f^{'} (x) = 3 x^{2} - 10 x - 8

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - \frac{2}{3}

into

x^{3} - 5 x^{2} - 8 x + 6 : \frac{238}{27}

Maximum (- \frac{2}{3}, \frac{238}{27})

Plug

x = 4

into

x^{3} - 5 x^{2} - 8 x + 6 : - 42

Minimum (4, - 42)

Maximum (- \frac{2}{3}, \frac{238}{27}), Minimum (4, - 42)

What is the extreme y=x^3-5x^2-8x+6 ?
The extreme y=x^3-5x^2-8x+6 is Maximum(-2/3 , 238/27),Minimum(4,-42)