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Popular >

distance (1,0),(0,2)

Solution

distance

(1, 0), (0, 2)

Solution

5

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(1, 0)

and

(0, 2)

is

= (0 - 1)^{2} + (2 - 0)^{2}

Simplify

= 5

Popular Examples

inverse of y=7x+8 inverse

y = 7 x + 8

extreme f(x)=sin^2(x/4)extreme points

f (x) = sin^{2} (\frac{x}{4})

domain of f(x)=\sqrt[3]{x^2-3}domain

parallel x-3y=-3 parallel

x - 3 y = - 3

inverse of f(x)= 1/3 (x^2+2)^{3/2}inverse

f (x) = \frac{1}{3} (x^{2} + 2)^{\frac{3}{2}}

Frequently Asked Questions (FAQ)

What is the distance (1,0),(0,2) ?
The distance (1,0),(0,2) is square root of 5