What is the extreme f(x)=18x^{2/3}-6x ?

The extreme f(x)=18x^{2/3}-6x is Minimum(0,0),Maximum(8,24)

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extreme f(x)=18x^{2/3}-6x

extreme points

f (x) = 18 x^{\frac{2}{3}} - 6 x

Minimum (0, 0), Maximum (8, 24)

Solution steps

f^{'} (x) = \frac{12}{x ^{\frac{1}{3}}} - 6

Find intervals:

Decreasing

: - \infty < x < \frac{1}{8},

Increasing

: \frac{1}{8} < x < \infty

Plug

x = 0

into

18 x^{\frac{2}{3}} - 6 x : 0

Minimum (0, 0)

Plug

x = 8

into

18 x^{\frac{2}{3}} - 6 x : 24

Maximum (8, 24)

Minimum (0, 0), Maximum (8, 24)

f (x) = \frac{3 x}{7 x - 6}

f (x) = 1 - x

6 tan (0.2 x)

f (x) = 2 x + 1

x + 4 y = 24

What is the extreme f(x)=18x^{2/3}-6x ?
The extreme f(x)=18x^{2/3}-6x is Minimum(0,0),Maximum(8,24)