What is the critical f(x)=cos^2(x) ?

The critical f(x)=cos^2(x) is x=pin,x= pi/2+pin

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critical f(x)=cos^2(x)

critical points

f (x) = cos^{2} (x)

x = πn, x = \frac{π}{2} + πn

Solution steps

cos^{2} (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = πn, x = \frac{π}{2} + πn

Identify critical points not in

f (x)

domain

Domain of

cos^{2} (x) : - \infty < x < \infty

All critical points are in domain

x = πn, x = \frac{π}{2} + πn

f (x) = 4 x - x^{2}

ln (x + 5)

f (x) = 14 (0.8)^{x}

f (x) = \frac{x}{1 - ln ( x - 8 )}

f (x) = 2^{x - 5} - 11

What is the critical f(x)=cos^2(x) ?
The critical f(x)=cos^2(x) is x=pin,x= pi/2+pin