What is the inverse of f(x)=2x^2-3x+1 ?

The inverse of f(x)=2x^2-3x+1 is (3+sqrt(8x+1))/4 ,(3-sqrt(8x+1))/4

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inverse of f(x)=2x^2-3x+1

inverse

f (x) = 2 x^{2} - 3 x + 1

\frac{3 + 8 x + 1}{4}, \frac{3 - 8 x + 1}{4}

Solution steps

y = 2 x^{2} - 3 x + 1

Replace

x

with

y

x = 2 y^{2} - 3 y + 1

Solve for

y, x = 2 y^{2} - 3 y + 1

\frac{3 + 8 x + 1}{4}, \frac{3 - 8 x + 1}{4}

3 x^{\frac{2}{3}} - x

\frac{5 x}{6 x - 1}

f (x) = x^{4} - 8 x^{2} + 2

f (x) = lo g_{\frac{1}{5}} (x)

f (x) = x^{4} - 2 x^{2}

What is the inverse of f(x)=2x^2-3x+1 ?
The inverse of f(x)=2x^2-3x+1 is (3+sqrt(8x+1))/4 ,(3-sqrt(8x+1))/4