What is the inverse of f(x)=(3x^2+4)/5 ?

The inverse of f(x)=(3x^2+4)/5 is sqrt((5x-4)/3),-sqrt((5x-4)/3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(3x^2+4)/5

inverse

f (x) = \frac{3 x ^{2} + 4}{5}

\frac{5 x - 4}{3}, - \frac{5 x - 4}{3}

Solution steps

y = \frac{3 x ^{2} + 4}{5}

Replace

x

with

y

x = \frac{3 y ^{2} + 4}{5}

Solve for

y, x = \frac{3 y ^{2} + 4}{5}

\frac{5 x - 4}{3}, - \frac{5 x - 4}{3}

f (x) = \frac{8}{- x ^{2} - 5 x + 14}

f (x) = \frac{8 x}{x - 2}

f (x) = x^{2} - 6 x + 5

f (x) = 2 sin (\frac{1}{2} x)

\frac{x + 5}{x - 1}

What is the inverse of f(x)=(3x^2+4)/5 ?
The inverse of f(x)=(3x^2+4)/5 is sqrt((5x-4)/3),-sqrt((5x-4)/3)