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Popular >

distance (-4,-4),(-3,0)

Solution

distance

(- 4, - 4), (- 3, 0)

Solution

17

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 4, - 4)

and

(- 3, 0)

is

= (- 3 - (- 4))^{2} + (0 - (- 4))^{2}

Simplify

= 17

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extreme f(x)=(1+x)/(sqrt(x))extreme points

f (x) = \frac{1 + x}{x}

slope of 10x-5y=3 slope

10 x - 5 y = 3

inflection f(x)=x^2ln(x/8)inflection points

f (x) = x^{2} ln (\frac{x}{8})

domain of f(x)=(9-x^2)/(2x^2)domain

f (x) = \frac{9 - x ^{2}}{2 x ^{2}}

intercepts of x^4-x^3-13x^2+25x-12 intercepts

x^{4} - x^{3} - 13 x^{2} + 25 x - 12

Frequently Asked Questions (FAQ)

What is the distance (-4,-4),(-3,0) ?
The distance (-4,-4),(-3,0) is square root of 17