What is the domain of f(x)= 1/(sqrt(x^2+2)) ?

The domain of f(x)= 1/(sqrt(x^2+2)) is -infinity <x<infinity

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domain of f(x)= 1/(sqrt(x^2+2))

domain

f (x) = \frac{1}{x ^{2} + 2}

- \infty < x < \infty

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 3 sin (3 x - 2)

f (x) = (1 - x)

f (x) = \frac{6 x + 7}{5 x - 6}

3 x + 4 y = 2

(x^{2} + 2 x - 1) (2 x^{2} - 3 x + 6)

What is the domain of f(x)= 1/(sqrt(x^2+2)) ?
The domain of f(x)= 1/(sqrt(x^2+2)) is -infinity <x<infinity