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Popular >

distance (0,6),(2,-2)

Solution

distance

(0, 6), (2, - 2)

Solution

217

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(0, 6)

and

(2, - 2)

is

= (2 - 0)^{2} + (- 2 - 6)^{2}

Simplify

= 217

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inverse of f(x)=8(\sqrt[4]{x}-10)inverse

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f (x) = \frac{4}{1 - 3 x}

range of f(x)=-3x^2-12x-9 range

f (x) = - 3 x^{2} - 12 x - 9

asymptotes of (x^3+5)/(x^5+2)asymptotes

\frac{x ^{3} + 5}{x ^{5} + 2}

perpendicular y= 3/4 x-31/4 ,(1,0)perpendicular

y = \frac{3}{4} x - \frac{31}{4}, (1, 0)

Frequently Asked Questions (FAQ)

What is the distance (0,6),(2,-2) ?
The distance (0,6),(2,-2) is 2sqrt(17)