What is the inverse of f(x)=(8x-1)/(3x+7) ?

The inverse of f(x)=(8x-1)/(3x+7) is (-1-7x)/(3x-8)

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inverse of f(x)=(8x-1)/(3x+7)

inverse

f (x) = \frac{8 x - 1}{3 x + 7}

\frac{- 1 - 7 x}{3 x - 8}

Solution steps

y = \frac{8 x - 1}{3 x + 7}

Replace

x

with

y

x = \frac{8 y - 1}{3 y + 7}

Solve for

y, x = \frac{8 y - 1}{3 y + 7}

\frac{- 1 - 7 x}{3 x - 8}

\frac{2 + x}{x - 5}

f (x) = x + 1

(0, 10), (8, 16)

f (x) = - 14 x - 8

\frac{∣ x ∣}{x}

What is the inverse of f(x)=(8x-1)/(3x+7) ?
The inverse of f(x)=(8x-1)/(3x+7) is (-1-7x)/(3x-8)