What is the domain of f(x)= x/(\sqrt[4]{36-x^2)} ?

The domain of f(x)= x/(\sqrt[4]{36-x^2)} is -6<x<6

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domain of f(x)= x/(\sqrt[4]{36-x^2)}

domain

- 6 < x < 6

Solution steps

Find non-negative values for radicals:

- 6 \leq x \leq 6

Find undefined (singularity) points:

x = 6, x = - 6

Combine real regions and undefined points for final function domain

- 6 < x < 6

\frac{1}{x + 5}

- \frac{3}{2} x - 1

f (x) = \frac{( e ^{x} )}{7 x}

7 x - 5 y = - 30

(- 3, 1), (- 1, - 1)

What is the domain of f(x)= x/(\sqrt[4]{36-x^2)} ?
The domain of f(x)= x/(\sqrt[4]{36-x^2)} is -6<x<6