What is the critical f(x)=2x^3+2x^2-2x ?

The critical f(x)=2x^3+2x^2-2x is x=-1,x= 1/3

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critical f(x)=2x^3+2x^2-2x

critical points

f (x) = 2 x^{3} + 2 x^{2} - 2 x

x = - 1, x = \frac{1}{3}

Solution steps

2 x^{3} + 2 x^{2} - 2 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = \frac{1}{3}

Identify critical points not in

f (x)

domain

Domain of

2 x^{3} + 2 x^{2} - 2 x : - \infty < x < \infty

All critical points are in domain

x = - 1, x = \frac{1}{3}

f (x) = - 6 x + 9

f (x) = \frac{e ^{x} - 1}{x}

(4, 1), (8, - 4)

f (x) = \frac{4 x}{x - 5}

f (x) = 4 x^{2} - 8 x - 1

What is the critical f(x)=2x^3+2x^2-2x ?
The critical f(x)=2x^3+2x^2-2x is x=-1,x= 1/3