What is the critical 2cos^2(x) ?

The critical 2cos^2(x) is x=pin,x= pi/2+pin

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critical 2cos^2(x)

critical points

2 cos^{2} (x)

x = πn, x = \frac{π}{2} + πn

Solution steps

2 cos^{2} (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = πn, x = \frac{π}{2} + πn

Identify critical points not in

f (x)

domain

Domain of

2 cos^{2} (x) : - \infty < x < \infty

All critical points are in domain

x = πn, x = \frac{π}{2} + πn

f (x) = x^{2} - 14 x + 45

16 - x^{2}

1 0^{x - 3}

\frac{1}{X ^{2}}

lo g_{5} (x) + 3 lo g_{25} (x)