What is the domain of f(x)=(sqrt(x+7))/(x-8) ?

The domain of f(x)=(sqrt(x+7))/(x-8) is -7 8

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domain of f(x)=(sqrt(x+7))/(x-8)

domain

f (x) = \frac{x + 7}{x - 8}

- 7 \leq x < 8 or x > 8

Solution steps

Find non-negative values for radicals:

x \geq - 7

Find undefined (singularity) points:

x = 8

Combine real regions and undefined points for final function domain

- 7 \leq x < 8 or x > 8

y = 2 x - cot^{2} (x)

x^{2} + 2 x - 2

21 6^{x}

f (x) = - 7 x + 1

f (x) = 48 x - 6 x^{2}

What is the domain of f(x)=(sqrt(x+7))/(x-8) ?
The domain of f(x)=(sqrt(x+7))/(x-8) is -7<= x<8\lor x>8