What is the extreme f(x)=x^4+16x^3-2 ?

The extreme f(x)=x^4+16x^3-2 is Minimum(-12,-6914),Saddle(0,-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^4+16x^3-2

extreme points

f (x) = x^{4} + 16 x^{3} - 2

Minimum (- 12, - 6914), Saddle (0, - 2)

Solution steps

f^{'} (x) = 4 x^{3} + 48 x^{2}

Find intervals:

Decreasing

: - \infty < x < - 12,

Increasing

: - 12 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 12

into

x^{4} + 16 x^{3} - 2 : - 6914

Minimum (- 12, - 6914)

Plug

x = 0

into

x^{4} + 16 x^{3} - 2 : - 2

Saddle (0, - 2)

Minimum (- 12, - 6914), Saddle (0, - 2)

3 x + 6

f (x) = \frac{1}{2} x^{2} + 2

f (x) = \frac{2 + x}{x - 5}

f (x) = 2 x - 3

f (x) = - 0.1 (x - 4)^{2} + 4.2

What is the extreme f(x)=x^4+16x^3-2 ?
The extreme f(x)=x^4+16x^3-2 is Minimum(-12,-6914),Saddle(0,-2)